Media Summary: More Matt: Matt Parker talks us through "Happification" and resulting structures it creates. Includes his ... Tadashi explores a special set of dice... And has a powerful lesson. More links & stuff in full description below ↓↓↓ Subscribe to ... Featuring Neil Sloane from the OEIS. Check out Brilliant (get 20% off their premium service):

Derangements Numberphile - Detailed Analysis & Overview

More Matt: Matt Parker talks us through "Happification" and resulting structures it creates. Includes his ... Tadashi explores a special set of dice... And has a powerful lesson. More links & stuff in full description below ↓↓↓ Subscribe to ... Featuring Neil Sloane from the OEIS. Check out Brilliant (get 20% off their premium service): 0! = 1 Dr James Grime tries to explain why this is the case - follow James on Twitter at More links ... Featuring Dr James Grime. More links & stuff in full description below ↓↓↓ Patreon: A quick little problem from Cliff Stoll, who baked a birthday cake for Brady... More links & stuff in full description below ↓↓↓ A ...

We revisit the philosophy department and the question of whether numbers really exist? Featuring Mark Jago from the University ... Featuring Simon Pampena... Check out Brilliant (and get 20% off their premium service): It was on Hilbert's list of the most important problems in mathematics - until his student solved it. More links & stuff in full ... Do political beliefs affect mathematical ability!? More links & stuff in full description below ↓↓↓ Featuring Dr James Grime. This is a (stand-alone) continuation of the previous video at: Featuring Tadashi Tokieda. James Maynard recently co-authored a proof of the Duffin-Schaeffer Conjecture. More links & stuff in full description below ...

A number which could earn its "finder" a $1000 prize. More links & stuff in full description below ↓↓↓ John Conway videos: ... Ken Ribet - a key player in the solution to Fermat's Last Theorem - gives a taste of how real mathematics is done... piece by piece ... Check out a recursive way for subfactorial here: Check out Best Friend 1/(1-x), ...

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