Page Summary: We can focus on a ≥ 0 because a ≤ 0 gives an upward parabola intersecting the top of the circle at a single real point. Selected region is also easy because both x and y are positive so x = x and y = y.

2018 Amc 10a Problem 12 -

We can focus on a ≥ 0 because a ≤ 0 gives an upward parabola intersecting the top of the circle at a single real point. Selected region is also easy because both x and y are positive so x = x and y = y.

Important details found

  • We can focus on a ≥ 0 because a ≤ 0 gives an upward parabola intersecting the top of the circle at a single real point.
  • Selected region is also easy because both x and y are positive so x = x and y = y.

Why this topic is useful

This topic is useful when readers need a quick overview first, then want to move into supporting details and related references.

Sponsored

Frequently Asked Questions

Why are related topics included?

Related topics help readers compare nearby references and understand the broader subject.

What is this page about?

This page summarizes 2018 Amc 10a Problem 12 and connects it with related entries, references, and supporting context.

Is the information always complete?

Not always. Some topics may need verification from official or primary sources.

Reference Gallery

2018 AMC 10A: Problem 12
2018 AMC 10A Prob 12  (12A Prob 10)
2018 AMC 10A: Problem 12
2018 AMC 10A Prob 17  (12A Prob 12)
2018 AMC 10A #12
2018 AMC 10A Prob 21  (12A Prob 16)
2018 AMC 10A Question 12
2018 AMC 10A Prob 13  (12A Prob 11)
2018 AMC 10A Prob 18  (12A Prob 13)
Art of Problem Solving: 2018 AMC 10 A #21 / AMC 12 A #16
Sponsored
View Full Details
2018 AMC 10A: Problem 12

2018 AMC 10A: Problem 12

Read more details and related context about 2018 AMC 10A: Problem 12.

2018 AMC 10A Prob 12  (12A Prob 10)

2018 AMC 10A Prob 12 (12A Prob 10)

Selected region is also easy because both x and y are positive so x = x and y = y.

2018 AMC 10A: Problem 12

2018 AMC 10A: Problem 12

Read more details and related context about 2018 AMC 10A: Problem 12.

2018 AMC 10A Prob 17  (12A Prob 12)

2018 AMC 10A Prob 17 (12A Prob 12)

Need to show that 2 also does not work for solution to be complete. Why not start with lower number cases and work your way ...

2018 AMC 10A #12

2018 AMC 10A #12

Read more details and related context about 2018 AMC 10A #12.

2018 AMC 10A Prob 21  (12A Prob 16)

2018 AMC 10A Prob 21 (12A Prob 16)

We can focus on a ≥ 0 because a ≤ 0 gives an upward parabola intersecting the top of the circle at a single real point.

2018 AMC 10A Question 12

2018 AMC 10A Question 12

Read more details and related context about 2018 AMC 10A Question 12.

2018 AMC 10A Prob 13  (12A Prob 11)

2018 AMC 10A Prob 13 (12A Prob 11)

Read more details and related context about 2018 AMC 10A Prob 13 (12A Prob 11).

2018 AMC 10A Prob 18  (12A Prob 13)

2018 AMC 10A Prob 18 (12A Prob 13)

Read more details and related context about 2018 AMC 10A Prob 18 (12A Prob 13).

Art of Problem Solving: 2018 AMC 10 A #21 / AMC 12 A #16

Art of Problem Solving: 2018 AMC 10 A #21 / AMC 12 A #16

Read more details and related context about Art of Problem Solving: 2018 AMC 10 A #21 / AMC 12 A #16.