Mat 230 8 11 2

We'll put zero into all the x locations so the inverse of sine of one think of your unit circle that would be pi over thing I'm concerned about with tangent of X is that there's vertical asymptotes at positive and negative pi over If x equals g of Y is a positive function that is a continuous derivative from C to D then my arc length will be

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• We'll put zero into all the x locations so the inverse of sine of one think of your unit circle that would be pi over
• thing I'm concerned about with tangent of X is that there's vertical asymptotes at positive and negative pi over
• If x equals g of Y is a positive function that is a continuous derivative from C to D then my arc length will be
• Gotta get rid of the division of 5 so we multiply 5 to both sides just as a note now that you have your X minus
• And yes there's a thunderstorm happening outside right now so we'll plug in our values pi over

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